(x+1)^2+2=3x-1

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Solution for (x+1)^2+2=3x-1 equation: 



(x+1)^2+2=3x-1

We move all terms to the left:

(x+1)^2+2-(3x-1)=0

We get rid of parentheses

(x+1)^2-3x+1+2=0

We add all the numbers together, and all the variables

-3x+(x+1)^2+3=0

We move all terms containing x to the left, all other terms to the right

-3x+(x+1)^2=-3

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